CSIR UGC NET 2020: Result (Out), Score Card, Cut Off, Admission Process
Updated On - January 16 2021 by Anusha Pachauri
CSIR UGC NET June 2020 scores has been announced by NTA. The answer keys and questions paper are available now NTA's site for June session. CSIR UGC NET was conducted on 19, 21 and 26 November 2020. Council of Scientific & Industrial Research UGC National Eligibility Test (June session) which will be conducted by the National Testing Agency (NTA). The exam is conducted twice in a year(June & December session) at the national level. Furthermore, this test determines the eligibility of candidates for Lectureship positions in Indian University/Colleges. Those who will clear JRF will be qualified for Lectureship subject to fulfilling the eligibility criteria laid down by UGC. The candidates must read the complete article to know all about CSIR UGC NET 2020 June session.
Candidate can check here all the important CSIR UGC 2020 dates for the application form in the given table below:
Start date of online application
16 March 2020
End date of online application
15 Jun 30 June 2020
Last date for the submission of fee payment
15 Jun 30 June 2020
Correction in Particulars of Application Form
06 Jul – 15 Jul 20 July 2020
Application Form Reopen from
22 August – 10 September 2020
Correction in Particulars of Application Form
11 – 17 September 2020
Correction in Test Centers
19 October to 20 October 2020
Admit card download date
7-26 November 2020
Date of Online examination
19, 21 & 26 November 2020
Release of answer key
03 December 2020
28 December 2020
Declarations of Results
05 Jul 2020 To be announced
CSIR UGC NET 2020 Result
The details regarding the CSIR UGC NET result 2020 are listed below. Also, the result will be declared on the official website of NTA.
The National Testing Agency (NTA) has declared the CSIR 2020 result, after releasing the CSIR NET final answer key.
Two separate merit list will be made based on the candidates' performance in the test.
Re-Evaluation/Re-Checking of the result: There shall be no re-evaluation/re-checking of the result. No correspondence/candidate in this regard shall be entertained.
CSIR NET result is declared in the form of merit list. The list carries the roll number and name of the qualifying candidness.
Moreover, candidates can also check the CSIR NET Scorecard. For this, they have to visit the website and log in using the application number and DOB.
On qualifying the examination, candidates are eligible to get appointed as Assistant Professorship and Junior Research Fellowship roles.
Candidates can download their e-certificate online from NTA/ CSIR NET website. They have to select the CSIR UGC NET option to download it.
CSIR NET Response Sheet 2020
Once the answer key is out, candidates are advised to visit the CSIR NET website to get the response sheet. Know more about SIR NET response sheet here.
To download CSIr NET response sheet, candidates have to visit csirnet.nta.nic.in. Thereafter, use the application number and date of birth to login and download the response sheet.
Response sheet carries the answers that are marked by the candidates in the examination.
Along with the response sheet, NTA also publishes CSIR NET question paper.
NTA publishes the CSIR NET response sheet after the release of provisional answer keys.
Candidates can compare their responses with the CSIR NET answer key to estimate their scores for the exam.
CSIR UGC NET 2020 Answer Key
The CSIR NET provisional answer key has been displayed along with the respective Question Paper on the official website of NTA after the conduction of exam. Candidates can check the important dates and the details related to Answer key 2020 below:
The NTA releases the CSIR UGC NET 2020 Answer Key on the official website after the successful commencement of the examination.
Answer Keys are to be displayed for two to three days to providing an opportunity for the candidates to challenge the Provisional Answer Key.
Candidates can challenge the answer key on payment of Rs. 1000/- per question challenged as processing charges.
The NTA decision on the challenges shall be final and the result will be declared based on final answer keys.
No grievances concerning Answer Key after the declaration of result will be entertained.
CSIR NET Mock Test 2020
Mock tests are effective in simulating the exam to the examinees before they actually appear for the exam. Solving mock tests can lead to the added advantage of efficient time management and setting an approach to solve the question paper. As the CSIR NET 2020 question paper consist of three parts, mocks tests can be effective in ensuring that candidates get accustomed with the question paper. Check out important tips and tricks related to CSIR NET 2020 mock tests below.
Simulate the CSIR NET 2020 exam pattern by setting exact durations for solving mock tests. Try to complete the test within the scheduled duration.
Strategize your approach to solve the question paper while solving mock tests. Switch between strategies to find out what works best.
Mock tests can also help identify the weaknesses and strengths of the candidate. Use this to your advantage.
Hall Ticket will not be sent by post to any candidate.
E-Admit Card will be issued by the NTA to those candidates only who will subject to the fulfilment of the eligibility conditions and fill the application form correctly.
Candidates will not be allowed to appear at the examination centre, on Date and Timings other than that allotted to them in their Admit card.
In case candidates are unable to download Admit Cards from the website or find any discrepancy in the admits card, then the candidate should approach the Help Line between 10:00 am to 5:00 pm.
The candidates must read the instructions on the Admit Card carefully and follow them during the conduct of the examination.
CSIR UGC NET 2020 Syllabus
The syllabus of the CSIR National Eligibility Test is released by the Human Resource Development Group, Council of Scientific & Industrial Research (CSIR - HRDG). The candidates can check the CSIR UGC NET Syllabus 2020given below. CSIR UGC NET June 2020 syllabus is as follows:
NOTE: National Testing Agency (NTA) will not provide a copy of the syllabus to individual candidates.
How to prepare for CSIR UGC NET 2020?
Various study materials are available in the commercial markets. Using them correctly should be a key strategy in preparing for CSIR NET 2020 exam. The examination consist of the three papers as described in preceding sections of this article. As the syllabus of the CSIR NET 2020 exam is vast, candidates can consider the following preparation tips to better equip themselves for the exam.
Set a study plan to cover the syllabus. Do not forget to include the syllabus of Paper I in the study plan.
Gather study materials relevant to the topics covered in the syllabus. A good way to go is to solve previous year question papers and mock tests.
It is natural to forget concepts learnt in the course of time. Make sure to dedicate time for revisions on a daily basis.
An advisable preparation strategy for the general aptitude part is to solve general aptitude papers from previous years and mock tests.
Books Recommended for Joint CSIR UGC NET Preparation
Selecting the most relevant books for CSIR NET 2020 preparation can be confusing. A wide variety of books from various publishers are available in the markets. Here we suggest the most important and latest books for CSIR NET 2020 preparation.
2020 EDITION General Aptitude: CSIR – UGC NET (JRF & LS) – For Part A
2020 EDITION Ace The Race ™ Combo 2: CSIR-UGC NET Life Sciences
Essential Competitive Chemistry for CSIR-NET/GATE-GRE 2020 Vol. 1 – Along with Solved Questions from Previous 15 Years
CSIR-UGC NET/JRF Earth, Atmospheric, Ocean and Planetary Sciences Exam Guide
CSIR UGC NET 2020 Exam Pattern
Candidates need to check the Paper Pattern of CSIR NET before they start preparing for the examination. The details about CSIR UGC NET 2020 Exam pattern is given below:
Mode of Examination: The exam will be conducted through Online mode (CBT) only.
Type of Questions: The questions asked will be of objective type, Multiple Choice Question (MCQ).
Exam Duration: The exam will be of 180 minutes (three hours) and there will be no break between papers.
Total Marks: The test paper for each subject shall carry a maximum of 200 marks.
The medium of Examination: The test will be in Hindi and English language. In case of any ambiguity between Hindi and English language due to translation, English medium would be treated as final.
Subjects of the Exam: The exam will be held in the five subjects: Chemical Sciences, Earth Sciences, Life Sciences, Mathematical Sciences, and Physical Sciences.
Sections: The test will consist of three parts/sections.
Part 'A' shall be common to all subjects. This part shall contain questions about General Aptitude with emphasis on logical reasoning, graphical analysis, analytical and numerical ability, quantitative comparison, series formation, puzzles, etc.
Part 'B' shall contain subject-related conventional Multiple Choice questions (MCQs), generally covering the topics given in the syllabus.
Part 'C' shall contain higher-order questions that may test the candidate's knowledge of scientific concepts and/or application of the scientific concepts.
CSIR UGC NET 2020 Application Form
CSIR UGC NET 2020 Application Form for June session has been released on the web portal of the NTA. The candidates can check all the details about CSIR UGC NET 2020 Application Form given below:
The application form can be filled through online mode only from 22 August to 10 September 2020.
No application will be accepted through offline mode or any other mode.
Candidates can submit one application only. Multiple applications will not be entertained.
Candidates have to provide a valid E-mail Address and Mobile Number in the Online Application Form as all information/communication will be sent by NTA through e-mail on the registered e-mail address or SMS on registered Mobile Number only.
Candidates also have to upload scanned images of Photograph and Signature in JPG/JPEG format.
All the instructions given in the Information Bulletin and on NTA website must be followed by the candidates while filling the application form.
Candidates must visit the NTA website and check their e-mails regularly for the latest updates.
It is mandatory to select four cities while filling the Online Application Form of CSIR UGC NET June 2020.
The entire application process of CSIR UGC NET June 2020 is online, so candidates do not need to send/submit any document(s) including Confirmation Page to NTA through Post/Fax/E-mail or by Hand.
CSIR UGC NET 2020 Application Fee
The application fee details for the CSIR NET 2020 is mentioned below:
Mode of Payment:
The application fee can be paid through Credit/Debit Card/Net Banking/UPI.
Candidates have to pay the fee by using SBI/Syndicate/HDFC/ICICI/Paytm Payment Gateway.
If in case Confirmation Page is not generated after the payment of fee, then it means that the transaction is cancelled, and the amount will be refunded automatically to the candidate’s account.
However, the candidate has to make another transaction, in case the Confirmation Page is not generated.
After successful payment of fee, candidates can download and print copies of Confirmation Page for future reference.
The list of CSIR UGC NET application Fees 2020 for different categories is given below in a table:
CSIR UGC NET Registration Fee 2020
General/General-EWS (Economically Weaker Section)
OBC-NCL (Non-Creamy Layer)
NOTE: The application fee of CSIR NET is non-refundable. So, any request by the candidate regarding the refund of fee will not be entertained by NTA under any circumstances.
CSIR UGC NET 2020 Application Form Correction
The NTA will facilitate the correction window for CSIR UGC NET 2020 for the candidates the dates for which will be notified. The applicants can make the changes (if required) in the application form online. The corrections in the form will be made only to some details.
CSIR UGC NET 2020 Eligibility Criteria
The candidates must check the CSIR UGC NET 2020 eligibility criteria before filling the application form to know their eligibility. If any candidate is found ineligible at any stage of exam will not be allowed for further process. The detailed eligibility of CSIR UGC National Eligibility Test 2020 is given hereby:
Junior Research Fellowship (JRF) - Candidates whose age is maximum 28 years as on 01 July 2020 are eligible. The upper age limit will be relaxable up to 5 years if a candidate is female or belong to SC/ST/Persons with Disability (PwD) category and 3 years of relaxation will be provided to OBC (Non-Creamy Layer) applicants.
Lectureship (LS)/ Assistant Professorship - There is no upper age limit in case of Assistant Professor/Lectureship.
Candidates who belong to General (UR)/General-EWS and OBC category must have a minimum of 55% marks in their M.Sc. or equivalent degree/Integrated BS-MS/BS-4 years/BE/B. Tech/B. Pharma/MBBS.
For SC/ST/Persons with Disability (PwD) candidates, minimum marks required to apply for the exam is 50%.
Candidates enrolled for M.Sc or having completed 3 years of the above qualifying examination/degree as on 09 October 2019, are also eligible to apply under the Result Awaited (RA) category.
For this, candidates will have to submit the attestation form duly certified by the Head of the Department/Institute from where the candidate is appearing or has appeared.
PhD degree holders who have passed Master’s degree before 19 September 1991 with at least 50% marks are eligible to apply for Lectureship/ Assistant Professorship only.
To determine the eligibility of the candidates for JRF (Junior Research Fellowship), Assistant professor/Lectureship positions.
About National Testing Agency
The NTA was established in November 2017 to conduct entrance examinations for higher educational institutions. NTA conducts the JEE Mains, NEET-UG, NET, CMAT & GPAT. Its actual start was in 2010 with a report submitted to the Ministry of Human Resources Development (MHRD) by a committee consisting of some of the directors of the Indian Institute of Technology which recommended that the national testing agency be "created by an Act of Parliament.
CSIR-UGC NET Important Dates
CSIR-UGC NET 2021 Form Date
15 Mar - 15 Apr 2021 (Tentative)
Council of Scientific & Industrial Research UGC NET June Exam Pattern
Question Paper Type :
Multiple Choice Questions
Frequently Asked Questions
Ques 1: What is CSIR UGC NET exam?
Ques 2: Is CSIR NET and UGC NET same?
Ques 3: How many attempts are allowed for CSIR NET?
Ques 4: What is the passing mark for NET exam?
Ques 5: How much is the stipend for JRF?
Ques 6: When Correction Window will open for CSIR-UGC NET Application form 2020?
Ques 7: Is CSIR UGC NET & CSIR NET different?
Ques 8: How may papers are there in csir ugc net?
Ques 9: When is the time to apply for dec UGC CSIR NET?